figure 1, circuits for question 1 
Circuit  Calculated Resistance  Meausred Resistance 
A  77.31 Ohms  78.2 Ohms 
B  378.33 Ohms  377 Ohms 
C  385.91 Ohms  385 Ohms 
In series, the DMM showed a current of about 40 mA, while in parallel, it showed 0 mA. This is due to the fact that when the current is measured in series, the current flows normally over the resistor and through the DMM. However in parallel, the resistor is shorted, making a resistance of nearly 0 Ohms. Due to Ohm's Law, I = V/R, this results in nearly infinite current. The DMM handles this by outputting 0 and giving an error notification.
Question 3: Apply 5 V to two resistors (47 Ω and 120 Ω) that are in series. Compare the measured and calculated values of voltage and current values on each resistor.
Measured:
Voltage across 47: 1.4 volts
Voltage across 120: 3.6 Volts
Current: 30 mA
Calculated:
Voltage across 47: 1.4 Volts
Voltage across 120: 3.59 Volts
Current: 29.9 mA
Voltage across 47: 1.4 Volts
Voltage across 120: 3.59 Volts
Current: 29.9 mA
Question 4: Apply 5 V to two resistors (47 Ω and 120 Ω) that are in parallel. Compare the measured and calculated values of voltage and current values on each resistor.
Measured:
Current across 47: .1 Amps
Current across 120: .03 Amps
Voltage 5 volts
Calculated:
Current across 47: .1068 Amps
Current across 120: .0418 Amps
Voltage 5 volts
Question 5: Compare the calculated and measured values of the following current and voltage for the circuit
below: (breadboard photo)
a. Current on 2 kΩ resistor,
b. Voltage across both 1.2 kΩ resistors.Current across 47: .1068 Amps
Current across 120: .0418 Amps
Voltage 5 volts


a.) we measured 2.06 mA on the 2k Ohms resistor.
b.) 1.) .863 Volts was measured across the first 1.2k Ohms resistor in the circuit from the power source
b.) 2.) .732 Volts was measured across the second 1.2k Ohms resistor in the circuit from the power source
Question 6: What would be the equivalent resistance value of the circuit above (between the power supply nodes)?
For the circuit above (figure 3) the calculated resistance we figured out was 2265.74 Ohms.
Question 7: Measure the equivalent resistance with and without the 5 V power supply. Are they different? Why?
Measuring the resistance without the power supply we got 2.464 kOhms. When we measured with the power supply we measured 0.563 kOhms. They were different because when you measure resistance with he power supply in line with the circuit also at the same points then the multimeter with measure the power supply's resistance in parallel with the circuit.
Question 8: Explain the operation of a potentiometer by measuring the resistance values between the terminals (there are 3 terminals, so there would be 3 combinations).(video)
figure 4, operation of a potentiometer
Question 9: What would be the minimum and maximum voltage that can be obtained at V1 by changing the knob position of the 5 KΩ pot? Explain.
figure 5, circuit for question 9 
figure 6, circuit for question 10 
When measuring V it 1 won't change at all because it is measured right at the voltage source but V2 will change as it is measured above the potentiometer acting as a variable resistor.
figure 7, video measuring V1 and V2
Question 11: For the circuit below, YOU SHOULD NOT turn down the potentiometer all the way down to reach 0 Ω. Why?
figure 8, circuit for question 11 
Question 12: . For the circuit above, how are current values of 1 kΩ resistor and 5 KΩ pot related and how do they change with the position of the knob of the pot? (video).
figure 9, video showing potentiometer
Question 13: Explain what a voltage divider is and how it works based on your experiments.
A voltage decider works by putting two resistors in series and taking voltage from the middle of the resistors. Because across the whole circuit with one resistor, if you apply 5 volts then you'd get 5 volts from the top to ground. With two resistors apply 5 volts there is a different voltage drop at the top of each of them in series. Therefore at the top of the second resistor in series you get a value between 5 and 0 volts.
Question 14: Explain what a current divider is and how it works based on your experiments.
A current divider is a way to control the input current source to a lower value. This is done with parallel resistors. In our experiment, we used a potentiometer for one of the resistors, allowing us to control the current using the knob.